What are the solutions to the equation X^2-10X+25=0 ?

The solutions to the equation X^2-10X+25=0 are X=5

Find the zeros of X^2-10X+25=0

The zeros of X^2-10X+25=0 are X=5

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X^{2} - 10 X + 25 = 0

X = 5

Solution steps

X^{2} - 10 X + 25 = 0

Solve with the quadratic formula

X_{1, 2} = \frac{- ( - 10 ) \pm ( - 10 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 10)^{2} - 4 \cdot 1 \cdot 25 = 0

X_{1, 2} = \frac{- ( - 10 ) \pm 0}{2 \cdot 1}

X = \frac{- ( - 10 )}{2 \cdot 1}

\frac{- ( - 10 )}{2 \cdot 1} = 5

X = 5

The solution to the quadratic equation is:

X = 5

x, f = 10 x^{2} ln (5 y + 3 z)

(x + 1)^{2} (x - 2) = x^{3} + 2 x^{2} - 5 x + 2

- 2 x^{2} + 128 = 0

2 x^{2} - 3 x - 1 = - x^{2} + 6 x - 7

x (3 x + 2) = (x + 2)^{2}

What are the solutions to the equation X^2-10X+25=0 ?
The solutions to the equation X^2-10X+25=0 are X=5
Find the zeros of X^2-10X+25=0
The zeros of X^2-10X+25=0 are X=5