What are the solutions to the equation 4x^2-24x+27=0 ?

The solutions to the equation 4x^2-24x+27=0 are x= 9/2 ,x= 3/2

Find the zeros of 4x^2-24x+27=0

The zeros of 4x^2-24x+27=0 are x= 9/2 ,x= 3/2

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4 x^{2} - 24 x + 27 = 0

x = \frac{9}{2}, x = \frac{3}{2}

Decimal Notation

x = 4.5, x = 1.5

Solution steps

4 x^{2} - 24 x + 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 24 ) \pm ( - 24 ) ^{2} - 4 \cdot 4 \cdot 27}{2 \cdot 4}

(- 24)^{2} - 4 \cdot 4 \cdot 27 = 12

x_{1, 2} = \frac{- ( - 24 ) \pm 12}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- ( - 24 ) + 12}{2 \cdot 4}, x_{2} = \frac{- ( - 24 ) - 12}{2 \cdot 4}

x = \frac{- ( - 24 ) + 12}{2 \cdot 4} : \frac{9}{2}

x = \frac{- ( - 24 ) - 12}{2 \cdot 4} : \frac{3}{2}

The solutions to the quadratic equation are:

x = \frac{9}{2}, x = \frac{3}{2}

4 x (x + 1) = 0

12 x^{2} + 8 = 0

25 w^{2} - 36 = 0

- 2 x^{2} - 6 x = 15

- \frac{1}{4} x^{2} + 5 x + 24 = 0

What are the solutions to the equation 4x^2-24x+27=0 ?
The solutions to the equation 4x^2-24x+27=0 are x= 9/2 ,x= 3/2
Find the zeros of 4x^2-24x+27=0
The zeros of 4x^2-24x+27=0 are x= 9/2 ,x= 3/2