What are the solutions to the equation 20^2=12^2+x^2 ?

The solutions to the equation 20^2=12^2+x^2 are x=16,x=-16

Find the zeros of 20^2=12^2+x^2

The zeros of 20^2=12^2+x^2 are x=16,x=-16

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2 0^{2} = 1 2^{2} + x^{2}

x = 16, x = - 16

Solution steps

2 0^{2} = 1 2^{2} + x^{2}

Switch sides

1 2^{2} + x^{2} = 2 0^{2}

Move

1 2^{2}

to the right side

x^{2} = 256

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = 256, x = - 256

256 = 16

- 256 = - 16

x = 16, x = - 16

2 y^{2} - 8 y + 7 = 0

x, x^{2} + y^{2} = - 4

x^{2} + 6 x + 10 = 0

30 x^{2} - 26 x + 4 = 0

6 x^{2} + 7 = 0

What are the solutions to the equation 20^2=12^2+x^2 ?
The solutions to the equation 20^2=12^2+x^2 are x=16,x=-16
Find the zeros of 20^2=12^2+x^2
The zeros of 20^2=12^2+x^2 are x=16,x=-16