What are the solutions to the equation t^2+9t=10 ?

The solutions to the equation t^2+9t=10 are t=1,t=-10

Find the zeros of t^2+9t=10

The zeros of t^2+9t=10 are t=1,t=-10

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t^{2} + 9 t = 10

t = 1, t = - 10

Solution steps

t^{2} + 9 t = 10

Move

10

to the left side

t^{2} + 9 t - 10 = 0

Solve with the quadratic formula

t_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 10 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 10) = 11

t_{1, 2} = \frac{- 9 \pm 11}{2 \cdot 1}

Separate the solutions

t_{1} = \frac{- 9 + 11}{2 \cdot 1}, t_{2} = \frac{- 9 - 11}{2 \cdot 1}

t = \frac{- 9 + 11}{2 \cdot 1} : 1

t = \frac{- 9 - 11}{2 \cdot 1} : - 10

The solutions to the quadratic equation are:

t = 1, t = - 10

6 x^{2} + 6 x - 12 = 0

y, (\frac{x}{7})^{2} + (\frac{y}{3})^{2} = 1

v^{2} = - 36

x^{2} + 2 x - x = 0

w^{2} - 2 w

What are the solutions to the equation t^2+9t=10 ?
The solutions to the equation t^2+9t=10 are t=1,t=-10
Find the zeros of t^2+9t=10
The zeros of t^2+9t=10 are t=1,t=-10