What are the solutions to the equation b^2-16b+64=0 ?

The solutions to the equation b^2-16b+64=0 are b=8

Find the zeros of b^2-16b+64=0

The zeros of b^2-16b+64=0 are b=8

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b^{2} - 16 b + 64 = 0

b = 8

Solution steps

b^{2} - 16 b + 64 = 0

Solve with the quadratic formula

b_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 1 \cdot 64}{2 \cdot 1}

(- 16)^{2} - 4 \cdot 1 \cdot 64 = 0

b_{1, 2} = \frac{- ( - 16 ) \pm 0}{2 \cdot 1}

b = \frac{- ( - 16 )}{2 \cdot 1}

\frac{- ( - 16 )}{2 \cdot 1} = 8

b = 8

The solution to the quadratic equation is:

b = 8

x^{2} + 6 x + 3 = 33

25 - x^{2} = \frac{74}{3}

(3 x - 18) (5 x - 10) = 0

(w + 6)^{2} = 3 (w + 12) - w^{2}

10 x^{2} = 16

What are the solutions to the equation b^2-16b+64=0 ?
The solutions to the equation b^2-16b+64=0 are b=8
Find the zeros of b^2-16b+64=0
The zeros of b^2-16b+64=0 are b=8