What are the solutions to the equation k^2-9k+8=0 ?

The solutions to the equation k^2-9k+8=0 are k=8,k=1

Find the zeros of k^2-9k+8=0

The zeros of k^2-9k+8=0 are k=8,k=1

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

k^{2} - 9 k + 8 = 0

k = 8, k = 1

Solution steps

k^{2} - 9 k + 8 = 0

Solve with the quadratic formula

k_{1, 2} = \frac{- ( - 9 ) \pm ( - 9 ) ^{2} - 4 \cdot 1 \cdot 8}{2 \cdot 1}

(- 9)^{2} - 4 \cdot 1 \cdot 8 = 7

k_{1, 2} = \frac{- ( - 9 ) \pm 7}{2 \cdot 1}

Separate the solutions

k_{1} = \frac{- ( - 9 ) + 7}{2 \cdot 1}, k_{2} = \frac{- ( - 9 ) - 7}{2 \cdot 1}

k = \frac{- ( - 9 ) + 7}{2 \cdot 1} : 8

k = \frac{- ( - 9 ) - 7}{2 \cdot 1} : 1

The solutions to the quadratic equation are:

k = 8, k = 1

0 = 3 x^{2} - 10 x - 8

3 x^{2} - 10 x - 3 = 0

r^{2} + 2 r + 9 = 0

x^{2} - 25 = 0

29 X^{2} - 1.2 X 1 0^{- 3} - 0.386 X = 0

What are the solutions to the equation k^2-9k+8=0 ?
The solutions to the equation k^2-9k+8=0 are k=8,k=1
Find the zeros of k^2-9k+8=0
The zeros of k^2-9k+8=0 are k=8,k=1