What are the solutions to the equation 6x^2+5x+8=0 ?

The solutions to the equation 6x^2+5x+8=0 are x=-5/12+i(sqrt(167))/(12),x=-5/12-i(sqrt(167))/(12)

Find the zeros of 6x^2+5x+8=0

The zeros of 6x^2+5x+8=0 are x=-5/12+i(sqrt(167))/(12),x=-5/12-i(sqrt(167))/(12)

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6 x^{2} + 5 x + 8 = 0

x = - \frac{5}{12} + i \frac{167}{12}, x = - \frac{5}{12} - i \frac{167}{12}

Solution steps

6 x^{2} + 5 x + 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 \pm 5 ^{2} - 4 \cdot 6 \cdot 8}{2 \cdot 6}

Simplify

5^{2} - 4 \cdot 6 \cdot 8 : 167 i

x_{1, 2} = \frac{- 5 \pm 167 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- 5 + 167 i}{2 \cdot 6}, x_{2} = \frac{- 5 - 167 i}{2 \cdot 6}

x = \frac{- 5 + 167 i}{2 \cdot 6} : - \frac{5}{12} + i \frac{167}{12}

x = \frac{- 5 - 167 i}{2 \cdot 6} : - \frac{5}{12} - i \frac{167}{12}

The solutions to the quadratic equation are:

x = - \frac{5}{12} + i \frac{167}{12}, x = - \frac{5}{12} - i \frac{167}{12}

a, (a + b)^{3} = a^{3} + b^{3}

x^{2} = 3 x - 4

x, (x - 5)^{2} - (y + 3)^{2} = 0

3 x^{2} - 5 x - 10 = x^{2} + 3 x + 14

x^{2} - 8 x = - 14

What are the solutions to the equation 6x^2+5x+8=0 ?
The solutions to the equation 6x^2+5x+8=0 are x=-5/12+i(sqrt(167))/(12),x=-5/12-i(sqrt(167))/(12)
Find the zeros of 6x^2+5x+8=0
The zeros of 6x^2+5x+8=0 are x=-5/12+i(sqrt(167))/(12),x=-5/12-i(sqrt(167))/(12)