What are the solutions to the equation 9n^2-12n+4=0 ?

The solutions to the equation 9n^2-12n+4=0 are n= 2/3

Find the zeros of 9n^2-12n+4=0

The zeros of 9n^2-12n+4=0 are n= 2/3

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9 n^{2} - 12 n + 4 = 0

n = \frac{2}{3}

Decimal

n = 0.66666 \dots

Solution steps

9 n^{2} - 12 n + 4 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- ( - 12 ) \pm ( - 12 ) ^{2} - 4 \cdot 9 \cdot 4}{2 \cdot 9}

(- 12)^{2} - 4 \cdot 9 \cdot 4 = 0

n_{1, 2} = \frac{- ( - 12 ) \pm 0}{2 \cdot 9}

n = \frac{- ( - 12 )}{2 \cdot 9}

\frac{- ( - 12 )}{2 \cdot 9} = \frac{2}{3}

n = \frac{2}{3}

The solution to the quadratic equation is:

n = \frac{2}{3}

(x + 6)^{2} = 2 x^{2} + 9 x + 18

x^{2} + 10 x - 1 = 0

2 x^{2} - 4 x + 1

- x^{2} - x - 3 = 2 x^{2} - 2 x - 3

s^{2} + 2 s + 8 = 0

What are the solutions to the equation 9n^2-12n+4=0 ?
The solutions to the equation 9n^2-12n+4=0 are n= 2/3
Find the zeros of 9n^2-12n+4=0
The zeros of 9n^2-12n+4=0 are n= 2/3