What are the solutions to the equation 9x^2-18x+29=0 ?

The solutions to the equation 9x^2-18x+29=0 are x=1+i(2sqrt(5))/3 ,x=1-i(2sqrt(5))/3

Find the zeros of 9x^2-18x+29=0

The zeros of 9x^2-18x+29=0 are x=1+i(2sqrt(5))/3 ,x=1-i(2sqrt(5))/3

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9 x^{2} - 18 x + 29 = 0

x = 1 + i \frac{2 5}{3}, x = 1 - i \frac{2 5}{3}

Solution steps

9 x^{2} - 18 x + 29 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 9 \cdot 29}{2 \cdot 9}

Simplify

(- 18)^{2} - 4 \cdot 9 \cdot 29 : 125 i

x_{1, 2} = \frac{- ( - 18 ) \pm 12 5 i}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 12 5 i}{2 \cdot 9}, x_{2} = \frac{- ( - 18 ) - 12 5 i}{2 \cdot 9}

x = \frac{- ( - 18 ) + 12 5 i}{2 \cdot 9} : 1 + i \frac{2 5}{3}

x = \frac{- ( - 18 ) - 12 5 i}{2 \cdot 9} : 1 - i \frac{2 5}{3}

The solutions to the quadratic equation are:

x = 1 + i \frac{2 5}{3}, x = 1 - i \frac{2 5}{3}

x, x^{2} - y^{2} - 4 x + 4 y = 0

7 x^{2} = - 2 x

- x^{2} + 4 x + 32 = 0

3 x^{2} + 6 x - 12 = 6 x

- 5 x^{2} - 15 x = 0

What are the solutions to the equation 9x^2-18x+29=0 ?
The solutions to the equation 9x^2-18x+29=0 are x=1+i(2sqrt(5))/3 ,x=1-i(2sqrt(5))/3
Find the zeros of 9x^2-18x+29=0
The zeros of 9x^2-18x+29=0 are x=1+i(2sqrt(5))/3 ,x=1-i(2sqrt(5))/3