What are the solutions to the equation 6p^2=13p-5 ?

The solutions to the equation 6p^2=13p-5 are p= 5/3 ,p= 1/2

Find the zeros of 6p^2=13p-5

The zeros of 6p^2=13p-5 are p= 5/3 ,p= 1/2

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6 p^{2} = 13 p - 5

p = \frac{5}{3}, p = \frac{1}{2}

Decimal

p = 1.66666 \dots, p = 0.5

Solution steps

6 p^{2} = 13 p - 5

Move

5

to the left side

6 p^{2} + 5 = 13 p

Move

13 p

to the left side

6 p^{2} + 5 - 13 p = 0

Write in the standard form

a x^{2} + b x + c = 0

6 p^{2} - 13 p + 5 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 13 ) \pm ( - 13 ) ^{2} - 4 \cdot 6 \cdot 5}{2 \cdot 6}

(- 13)^{2} - 4 \cdot 6 \cdot 5 = 7

p_{1, 2} = \frac{- ( - 13 ) \pm 7}{2 \cdot 6}

Separate the solutions

p_{1} = \frac{- ( - 13 ) + 7}{2 \cdot 6}, p_{2} = \frac{- ( - 13 ) - 7}{2 \cdot 6}

p = \frac{- ( - 13 ) + 7}{2 \cdot 6} : \frac{5}{3}

p = \frac{- ( - 13 ) - 7}{2 \cdot 6} : \frac{1}{2}

The solutions to the quadratic equation are:

p = \frac{5}{3}, p = \frac{1}{2}

(y - 1)^{2} = 0

(x - 3)^{2} = - 8

833.6 = - 0.6 q^{2} + 9.6 q + 450

s^{2} - 7 s + 10 = 0

n^{2} - 6 n - 40 = 0

What are the solutions to the equation 6p^2=13p-5 ?
The solutions to the equation 6p^2=13p-5 are p= 5/3 ,p= 1/2
Find the zeros of 6p^2=13p-5
The zeros of 6p^2=13p-5 are p= 5/3 ,p= 1/2