What are the solutions to the equation 400=-16t^2+800 ?

The solutions to the equation 400=-16t^2+800 are t=5,t=-5

Find the zeros of 400=-16t^2+800

The zeros of 400=-16t^2+800 are t=5,t=-5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

400 = - 16 t^{2} + 800

t = 5, t = - 5

Solution steps

400 = - 16 t^{2} + 800

Switch sides

- 16 t^{2} + 800 = 400

Move

800

to the right side

- 16 t^{2} = - 400

Divide both sides by

- 16

t^{2} = 25

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

t = 25, t = - 25

25 = 5

- 25 = - 5

t = 5, t = - 5

3 \frac{1}{5} x^{2} \frac{5}{8} = 8 \frac{2}{5}

3 x^{2} + 10 x = - 8

x^{2} = 4 x - 8

x^{2} + 3 x = - 7

3 x^{2} + 1 = 73

What are the solutions to the equation 400=-16t^2+800 ?
The solutions to the equation 400=-16t^2+800 are t=5,t=-5
Find the zeros of 400=-16t^2+800
The zeros of 400=-16t^2+800 are t=5,t=-5