What are the solutions to the equation ax^2+4x-ax-4=0 ?

The solutions to the equation ax^2+4x-ax-4=0 are x=1,x=-4/a ;\quad a\ne 0

Find the zeros of ax^2+4x-ax-4=0

The zeros of ax^2+4x-ax-4=0 are x=1,x=-4/a ;\quad a\ne 0

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a x^{2} + 4 x - a x - 4 = 0

x = 1, x = - \frac{4}{a}; a \neq = 0

Solution steps

a x^{2} + 4 x - a x - 4 = 0

Write in the standard form

a x^{2} + b x + c = 0

a x^{2} + (4 - a) x - 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( 4 - a ) \pm ( 4 - a ) ^{2} - 4 a ( - 4 )}{2 a}

Simplify

(4 - a)^{2} - 4 a (- 4) : a + 4

x_{1, 2} = \frac{- ( 4 - a ) \pm ( a + 4 )}{2 a}; a \neq = 0

Separate the solutions

x_{1} = \frac{- ( 4 - a ) + a + 4}{2 a}, x_{2} = \frac{- ( 4 - a ) - ( a + 4 )}{2 a}

x = \frac{- ( 4 - a ) + a + 4}{2 a} : 1

x = \frac{- ( 4 - a ) - ( a + 4 )}{2 a} : - \frac{4}{a}

The solutions to the quadratic equation are:

x = 1, x = - \frac{4}{a}; a \neq = 0

\frac{4 x ^{2} - 9 x}{3} = 0

0 = x^{2} - 10 x + 24

5 (x + 4)^{2} = 2 (x + 1)^{2} - 27

x^{2} - 100 x + 2500 = 1152 π^{2} x - 56700 π^{2}

x^{2} - x - 21 = 0

What are the solutions to the equation ax^2+4x-ax-4=0 ?
The solutions to the equation ax^2+4x-ax-4=0 are x=1,x=-4/a ;\quad a\ne 0
Find the zeros of ax^2+4x-ax-4=0
The zeros of ax^2+4x-ax-4=0 are x=1,x=-4/a ;\quad a\ne 0