What are the solutions to the equation 3x^2+11=0 ?

The solutions to the equation 3x^2+11=0 are x=sqrt(11/3)i,x=-sqrt(11/3)i

Find the zeros of 3x^2+11=0

The zeros of 3x^2+11=0 are x=sqrt(11/3)i,x=-sqrt(11/3)i

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3 x^{2} + 11 = 0

x = \frac{11}{3} i, x = - \frac{11}{3} i

Solution steps

3 x^{2} + 11 = 0

Move

11

to the right side

3 x^{2} = - 11

Divide both sides by

3

x^{2} = - \frac{11}{3}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - \frac{11}{3}, x = - - \frac{11}{3}

- \frac{11}{3} = \frac{11}{3} i

- - \frac{11}{3} = - \frac{11}{3} i

x = \frac{11}{3} i, x = - \frac{11}{3} i

- 2 x = x^{2} + 1

(x - 7) (x + 6) = 0

y, x^{3} + y^{2} = y + x

x, 4 y^{3} + 4 x^{2} y - 2 y - 6 = 0

2 x (x + 3) = 15

What are the solutions to the equation 3x^2+11=0 ?
The solutions to the equation 3x^2+11=0 are x=sqrt(11/3)i,x=-sqrt(11/3)i
Find the zeros of 3x^2+11=0
The zeros of 3x^2+11=0 are x=sqrt(11/3)i,x=-sqrt(11/3)i