What are the solutions to the equation 989-264x+12x^2=0 ?

The solutions to the equation 989-264x+12x^2=0 are x=(66+sqrt(1389))/6 ,x=(66-sqrt(1389))/6

Find the zeros of 989-264x+12x^2=0

The zeros of 989-264x+12x^2=0 are x=(66+sqrt(1389))/6 ,x=(66-sqrt(1389))/6

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989 - 264 x + 12 x^{2} = 0

x = \frac{66 + 1389}{6}, x = \frac{66 - 1389}{6}

Decimal Notation

x = 17.21154 \dots, x = 4.78845 \dots

Solution steps

989 - 264 x + 12 x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

12 x^{2} - 264 x + 989 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 264 ) \pm ( - 264 ) ^{2} - 4 \cdot 12 \cdot 989}{2 \cdot 12}

(- 264)^{2} - 4 \cdot 12 \cdot 989 = 41389

x_{1, 2} = \frac{- ( - 264 ) \pm 4 1389}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- ( - 264 ) + 4 1389}{2 \cdot 12}, x_{2} = \frac{- ( - 264 ) - 4 1389}{2 \cdot 12}

x = \frac{- ( - 264 ) + 4 1389}{2 \cdot 12} : \frac{66 + 1389}{6}

x = \frac{- ( - 264 ) - 4 1389}{2 \cdot 12} : \frac{66 - 1389}{6}

The solutions to the quadratic equation are:

x = \frac{66 + 1389}{6}, x = \frac{66 - 1389}{6}

x, f = \frac{3 x ^{2} - 3 x - 60}{h}

x^{2} - 10 x - 5 = 9

(x - 5)^{2} = 100

(u + 2) (u + 1) + (u + 1) (3 u - 1) = (6 - u) (3 u - 1)

x^{2} + x = - 6

What are the solutions to the equation 989-264x+12x^2=0 ?
The solutions to the equation 989-264x+12x^2=0 are x=(66+sqrt(1389))/6 ,x=(66-sqrt(1389))/6
Find the zeros of 989-264x+12x^2=0
The zeros of 989-264x+12x^2=0 are x=(66+sqrt(1389))/6 ,x=(66-sqrt(1389))/6