What are the solutions to the equation (3x-5)(x+4)=0 ?

The solutions to the equation (3x-5)(x+4)=0 are x= 5/3 ,x=-4

Find the zeros of (3x-5)(x+4)=0

The zeros of (3x-5)(x+4)=0 are x= 5/3 ,x=-4

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(3 x - 5) (x + 4) = 0

x = \frac{5}{3}, x = - 4

Decimal Notation

x = 1.66666 \dots, x = - 4

Solution steps

(3 x - 5) (x + 4) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

3 x - 5 = 0 or x + 4 = 0

Solve

3 x - 5 = 0 : x = \frac{5}{3}

Solve

x + 4 = 0 : x = - 4

The solutions to the quadratic equation are:

x = \frac{5}{3}, x = - 4

x, f = x^{2} + 3 x yz + y z^{3} + 2

- 6 x^{2} + 222 x - 1872 = 0

3 x^{2} - 10 = 8 x

t, \int x d x = 3 t^{2}

(x - 2) (x + 2) - 12 = 0

What are the solutions to the equation (3x-5)(x+4)=0 ?
The solutions to the equation (3x-5)(x+4)=0 are x= 5/3 ,x=-4
Find the zeros of (3x-5)(x+4)=0
The zeros of (3x-5)(x+4)=0 are x= 5/3 ,x=-4