What are the solutions to the equation a^2+8a+7=0 ?

The solutions to the equation a^2+8a+7=0 are a=-1,a=-7

Find the zeros of a^2+8a+7=0

The zeros of a^2+8a+7=0 are a=-1,a=-7

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a^{2} + 8 a + 7 = 0

a = - 1, a = - 7

Solution steps

a^{2} + 8 a + 7 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 7}{2 \cdot 1}

8^{2} - 4 \cdot 1 \cdot 7 = 6

a_{1, 2} = \frac{- 8 \pm 6}{2 \cdot 1}

Separate the solutions

a_{1} = \frac{- 8 + 6}{2 \cdot 1}, a_{2} = \frac{- 8 - 6}{2 \cdot 1}

a = \frac{- 8 + 6}{2 \cdot 1} : - 1

a = \frac{- 8 - 6}{2 \cdot 1} : - 7

The solutions to the quadratic equation are:

a = - 1, a = - 7

x^{2} - 16

t, h = - \frac{1}{2} a t^{2} + 1

\frac{14}{15} x^{2} - 9 - \frac{11}{2} x = 0

m^{2} - 8 = 0

(x + 4)^{2} = 1

What are the solutions to the equation a^2+8a+7=0 ?
The solutions to the equation a^2+8a+7=0 are a=-1,a=-7
Find the zeros of a^2+8a+7=0
The zeros of a^2+8a+7=0 are a=-1,a=-7