What are the solutions to the equation 4-4x^2+15x=0 ?

The solutions to the equation 4-4x^2+15x=0 are x=-1/4 ,x=4

Find the zeros of 4-4x^2+15x=0

The zeros of 4-4x^2+15x=0 are x=-1/4 ,x=4

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4 - 4 x^{2} + 15 x = 0

x = - \frac{1}{4}, x = 4

Decimal Notation

x = - 0.25, x = 4

Solution steps

4 - 4 x^{2} + 15 x = 0

Write in the standard form

a x^{2} + b x + c = 0

- 4 x^{2} + 15 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 15 \pm 1 5 ^{2} - 4 ( - 4 ) \cdot 4}{2 ( - 4 )}

1 5^{2} - 4 (- 4) \cdot 4 = 17

x_{1, 2} = \frac{- 15 \pm 17}{2 ( - 4 )}

Separate the solutions

x_{1} = \frac{- 15 + 17}{2 ( - 4 )}, x_{2} = \frac{- 15 - 17}{2 ( - 4 )}

x = \frac{- 15 + 17}{2 ( - 4 )} : - \frac{1}{4}

x = \frac{- 15 - 17}{2 ( - 4 )} : 4

The solutions to the quadratic equation are:

x = - \frac{1}{4}, x = 4

m^{2} + 12 m = 3

- 0.002 x^{2} - 0.4 x + 230 = 0.0004 x^{2} + 0.1 x + 156

(x - 7) (x + 9) = 0

x, x^{2} + 23 x y - y^{2} + 2 = 0

x^{2} = - 10 x - 1

What are the solutions to the equation 4-4x^2+15x=0 ?
The solutions to the equation 4-4x^2+15x=0 are x=-1/4 ,x=4
Find the zeros of 4-4x^2+15x=0
The zeros of 4-4x^2+15x=0 are x=-1/4 ,x=4