What are the solutions to the equation factor 2x^2+x-3=0 ?

The solutions to the equation factor 2x^2+x-3=0 are x=1,x=-3/2

Find the zeros of factor 2x^2+x-3=0

The zeros of factor 2x^2+x-3=0 are x=1,x=-3/2

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2 x^{2} + x - 3 = 0

x = 1, x = - \frac{3}{2}

Decimal Notation

x = 1, x = - 1.5

Solution steps

2 x^{2} + x - 3 = 0

Factor

2 x^{2} + x - 3 : (x - 1) (2 x + 3)

(x - 1) (2 x + 3) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

x - 1 = 0 or 2 x + 3 = 0

Solve

x - 1 = 0 : x = 1

Solve

2 x + 3 = 0 : x = - \frac{3}{2}

The solutions to the quadratic equation are:

x = 1, x = - \frac{3}{2}

4 v^{2} + 12 v = 0

5 + 6 x - x^{2} = 0

2 x^{2} - 6 x + 5

r, S = r - rr

3 x^{2} - 24 x - 48 = 0

What are the solutions to the equation factor 2x^2+x-3=0 ?
The solutions to the equation factor 2x^2+x-3=0 are x=1,x=-3/2
Find the zeros of factor 2x^2+x-3=0
The zeros of factor 2x^2+x-3=0 are x=1,x=-3/2