What are the solutions to the equation e=(v^2)/(2a) ?

The solutions to the equation e=(v^2)/(2a) are v=sqrt(2)sqrt(ea),v=-sqrt(2)sqrt(ea);\quad a\ne 0

Find the zeros of e=(v^2)/(2a)

The zeros of e=(v^2)/(2a) are v=sqrt(2)sqrt(ea),v=-sqrt(2)sqrt(ea);\quad a\ne 0

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e = \frac{v ^{2}}{2 a}

v = 2 e a, v = - 2 e a; a \neq = 0

Solution steps

e = \frac{v ^{2}}{2 a}

Switch sides

\frac{v ^{2}}{2 a} = e

Multiply both sides by

2 a

v^{2} = e 2 a; a \neq = 0

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

v = e 2 a, v = - e 2 a; a \neq = 0

Simplify

e 2 a : 2 e a

Simplify

- e 2 a : - 2 e a

v = 2 e a, v = - 2 e a; a \neq = 0

x^{2} - 12 x + 44 = 0

2 x^{2} - 8 x + 6

5 k^{2} + 6 k - 32 = - 12

(x + 2) (x - 3) - x (2 x + 1) + 6 x = 0

4 x^{2} - 2 = 94

What are the solutions to the equation e=(v^2)/(2a) ?
The solutions to the equation e=(v^2)/(2a) are v=sqrt(2)sqrt(ea),v=-sqrt(2)sqrt(ea);\quad a\ne 0
Find the zeros of e=(v^2)/(2a)
The zeros of e=(v^2)/(2a) are v=sqrt(2)sqrt(ea),v=-sqrt(2)sqrt(ea);\quad a\ne 0