What are the solutions to the equation completesquare x^2+4x-12=0 ?

The solutions to the equation completesquare x^2+4x-12=0 are x=2,x=-6

Find the zeros of completesquare x^2+4x-12=0

The zeros of completesquare x^2+4x-12=0 are x=2,x=-6

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x^{2} + 4 x - 12 = 0

x = 2, x = - 6

Solution steps

x^{2} + 4 x - 12 = 0

Move

12

to the right side

x^{2} + 4 x = 12

Rewrite in the form

(x + a)^{2} = b

(x + 2)^{2} = 16

For

the solutions are

f (x) = a, - a

Solve

x + 2 = 16 : x = 2

Solve

x + 2 = - 16 : x = - 6

The solutions to the quadratic equation are:

x = 2, x = - 6

- 13 y - (y - 4) 2 + 8 (2 y - 3) = 8 - (y + 5) (y - 5) - 10 (y + 1)

x^{2} - 37 x + 311 = 0

g = 10 + 0.9 v - 0.01 v^{2}

6 x = - 12 x^{2}

x^{2} + 4 x + 6 = 0

What are the solutions to the equation completesquare x^2+4x-12=0 ?
The solutions to the equation completesquare x^2+4x-12=0 are x=2,x=-6
Find the zeros of completesquare x^2+4x-12=0
The zeros of completesquare x^2+4x-12=0 are x=2,x=-6