What are the solutions to the equation -x^2+4x+c=0 ?

The solutions to the equation -x^2+4x+c=0 are x=2-sqrt(c+4),x=sqrt(c+4)+2

Find the zeros of -x^2+4x+c=0

The zeros of -x^2+4x+c=0 are x=2-sqrt(c+4),x=sqrt(c+4)+2

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- x^{2} + 4 x + c = 0

x = 2 - c + 4, x = c + 4 + 2

Solution steps

- x^{2} + 4 x + c = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 4 \pm 4 ^{2} - 4 ( - 1 ) c}{2 ( - 1 )}

Simplify

4^{2} - 4 (- 1) c : 2 4 + c

x_{1, 2} = \frac{- 4 \pm 2 4 + c}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 4 + 2 4 + c}{2 ( - 1 )}, x_{2} = \frac{- 4 - 2 4 + c}{2 ( - 1 )}

x = \frac{- 4 + 2 4 + c}{2 ( - 1 )} : 2 - c + 4

x = \frac{- 4 - 2 4 + c}{2 ( - 1 )} : c + 4 + 2

The solutions to the quadratic equation are:

x = 2 - c + 4, x = c + 4 + 2

16 x^{2} + 64 = 0

7 x^{2} = 3 x

7 x^{2} = 21

(x + \frac{1}{2})^{2} = \frac{4}{9}

14 x^{2} + 9 x + 1 = 0

What are the solutions to the equation -x^2+4x+c=0 ?
The solutions to the equation -x^2+4x+c=0 are x=2-sqrt(c+4),x=sqrt(c+4)+2
Find the zeros of -x^2+4x+c=0
The zeros of -x^2+4x+c=0 are x=2-sqrt(c+4),x=sqrt(c+4)+2