What are the solutions to the equation completesquare 7t^2+28t+56=0 ?

The solutions to the equation completesquare 7t^2+28t+56=0 are t=2i-2,t=-2i-2

Find the zeros of completesquare 7t^2+28t+56=0

The zeros of completesquare 7t^2+28t+56=0 are t=2i-2,t=-2i-2

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7 t^{2} + 28 t + 56 = 0

t = 2 i - 2, t = - 2 i - 2

Solution steps

7 t^{2} + 28 t + 56 = 0

Move

56

to the right side

7 t^{2} + 28 t = - 56

Divide both sides by

7

\frac{7 t ^{2} + 28 t}{7} = \frac{- 56}{7}

t^{2} + 4 t = - 8

Rewrite in the form

(x + a)^{2} = b

(t + 2)^{2} = - 4

For

the solutions are

f (x) = a, - a

Solve

t + 2 = - 4 : t = 2 i - 2

Solve

t + 2 = - - 4 : t = - 2 i - 2

The solutions to the quadratic equation are:

t = 2 i - 2, t = - 2 i - 2

9 x - 9 = - 4 x^{2}

x^{2} - 40 x + 144 = 0

x^{2} - 84 = - 3

- 7 x^{2} + 23 x = 180

6 (x^{2} - 4) = 0

What are the solutions to the equation completesquare 7t^2+28t+56=0 ?
The solutions to the equation completesquare 7t^2+28t+56=0 are t=2i-2,t=-2i-2
Find the zeros of completesquare 7t^2+28t+56=0
The zeros of completesquare 7t^2+28t+56=0 are t=2i-2,t=-2i-2