What are the solutions to the equation solvefor x,0=12x^2+5yx-3y^2 ?

The solutions to the equation solvefor x,0=12x^2+5yx-3y^2 are x= y/3 ,x=-(3y)/4

Find the zeros of solvefor x,0=12x^2+5yx-3y^2

The zeros of solvefor x,0=12x^2+5yx-3y^2 are x= y/3 ,x=-(3y)/4

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solve for

x, 0 = 12 x^{2} + 5 y x - 3 y^{2}

x = \frac{y}{3}, x = - \frac{3 y}{4}

Solution steps

0 = 12 x^{2} + 5 y x - 3 y^{2}

Switch sides

12 x^{2} + 5 y x - 3 y^{2} = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 5 y \pm ( 5 y ) ^{2} - 4 \cdot 12 ( - 3 y ^{2} )}{2 \cdot 12}

Simplify

(5 y)^{2} - 4 \cdot 12 (- 3 y^{2}) : 13 y

x_{1, 2} = \frac{- 5 y \pm 13 y}{2 \cdot 12}

Separate the solutions

x_{1} = \frac{- 5 y + 13 y}{2 \cdot 12}, x_{2} = \frac{- 5 y - 13 y}{2 \cdot 12}

x = \frac{- 5 y + 13 y}{2 \cdot 12} : \frac{y}{3}

x = \frac{- 5 y - 13 y}{2 \cdot 12} : - \frac{3 y}{4}

The solutions to the quadratic equation are:

x = \frac{y}{3}, x = - \frac{3 y}{4}

x^{2} + 12 x = - 3

6 x^{2} - 12 x = 48

0.25 x^{2} + 8.5 x - 17 = 0

2 x^{2} - 5 x - 84 = - 3 x

v^{2} + 6 v + 5 = 0

What are the solutions to the equation solvefor x,0=12x^2+5yx-3y^2 ?
The solutions to the equation solvefor x,0=12x^2+5yx-3y^2 are x= y/3 ,x=-(3y)/4
Find the zeros of solvefor x,0=12x^2+5yx-3y^2
The zeros of solvefor x,0=12x^2+5yx-3y^2 are x= y/3 ,x=-(3y)/4