What are the solutions to the equation 8y^2-16y=0 ?

The solutions to the equation 8y^2-16y=0 are y=2,y=0

Find the zeros of 8y^2-16y=0

The zeros of 8y^2-16y=0 are y=2,y=0

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8 y^{2} - 16 y = 0

y = 2, y = 0

Solution steps

8 y^{2} - 16 y = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 16 ) \pm ( - 16 ) ^{2} - 4 \cdot 8 \cdot 0}{2 \cdot 8}

(- 16)^{2} - 4 \cdot 8 \cdot 0 = 16

y_{1, 2} = \frac{- ( - 16 ) \pm 16}{2 \cdot 8}

Separate the solutions

y_{1} = \frac{- ( - 16 ) + 16}{2 \cdot 8}, y_{2} = \frac{- ( - 16 ) - 16}{2 \cdot 8}

y = \frac{- ( - 16 ) + 16}{2 \cdot 8} : 2

y = \frac{- ( - 16 ) - 16}{2 \cdot 8} : 0

The solutions to the quadratic equation are:

y = 2, y = 0

g (n) = n^{2} + 2, g (3)

x^{2} - (a - 2) x - 2 a^{2} + 5 a - 3 = 0

x^{2} - 6 x - 3 = 0

x^{2} - 2 x - 35

x, x^{2} + x y = 5

What are the solutions to the equation 8y^2-16y=0 ?
The solutions to the equation 8y^2-16y=0 are y=2,y=0
Find the zeros of 8y^2-16y=0
The zeros of 8y^2-16y=0 are y=2,y=0