What are the solutions to the equation (x+5)(x+4)=156 ?

The solutions to the equation (x+5)(x+4)=156 are x=8,x=-17

Find the zeros of (x+5)(x+4)=156

The zeros of (x+5)(x+4)=156 are x=8,x=-17

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(x + 5) (x + 4) = 156

x = 8, x = - 17

Solution steps

(x + 5) (x + 4) = 156

Expand

(x + 5) (x + 4) : x^{2} + 9 x + 20

x^{2} + 9 x + 20 = 156

Move

156

to the left side

x^{2} + 9 x - 136 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 9 \pm 9 ^{2} - 4 \cdot 1 \cdot ( - 136 )}{2 \cdot 1}

9^{2} - 4 \cdot 1 \cdot (- 136) = 25

x_{1, 2} = \frac{- 9 \pm 25}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 9 + 25}{2 \cdot 1}, x_{2} = \frac{- 9 - 25}{2 \cdot 1}

x = \frac{- 9 + 25}{2 \cdot 1} : 8

x = \frac{- 9 - 25}{2 \cdot 1} : - 17

The solutions to the quadratic equation are:

x = 8, x = - 17

9 x^{2} - 63 = 8 x^{2} + 2 x

2 (x + \frac{1}{2})^{2} + \frac{25 x}{2} = (\frac{1}{2} - x) (7 x + 1) - 4

2 x^{2} = x - 7

- 17 x = 5 - 12 x^{2}

x^{2} + 6 x + 5 = 8

What are the solutions to the equation (x+5)(x+4)=156 ?
The solutions to the equation (x+5)(x+4)=156 are x=8,x=-17
Find the zeros of (x+5)(x+4)=156
The zeros of (x+5)(x+4)=156 are x=8,x=-17