What are the solutions to the equation 0=-16x^2+35x+6.5 ?

The solutions to the equation 0=-16x^2+35x+6.5 are x=-(-35+sqrt(1641))/(32),x=(35+sqrt(1641))/(32)

Find the zeros of 0=-16x^2+35x+6.5

The zeros of 0=-16x^2+35x+6.5 are x=-(-35+sqrt(1641))/(32),x=(35+sqrt(1641))/(32)

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0 = - 16 x^{2} + 35 x + 6.5

x = - \frac{- 35 + 1641}{32}, x = \frac{35 + 1641}{32}

Decimal Notation

x = - 0.17216 \dots, x = 2.35966 \dots

Solution steps

0 = - 16 x^{2} + 35 x + 6.5

Multiply both sides by

10

0 = - 160 x^{2} + 350 x + 65

Switch sides

- 160 x^{2} + 350 x + 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 350 \pm 35 0 ^{2} - 4 ( - 160 ) \cdot 65}{2 ( - 160 )}

35 0^{2} - 4 (- 160) \cdot 65 = 101641

x_{1, 2} = \frac{- 350 \pm 10 1641}{2 ( - 160 )}

Separate the solutions

x_{1} = \frac{- 350 + 10 1641}{2 ( - 160 )}, x_{2} = \frac{- 350 - 10 1641}{2 ( - 160 )}

x = \frac{- 350 + 10 1641}{2 ( - 160 )} : - \frac{- 35 + 1641}{32}

x = \frac{- 350 - 10 1641}{2 ( - 160 )} : \frac{35 + 1641}{32}

The solutions to the quadratic equation are:

x = - \frac{- 35 + 1641}{32}, x = \frac{35 + 1641}{32}

(3 x + 1)^{2} - 16 = 0

z^{2} = - 49

29 x^{2} - 4 x + 1 = 0

x^{2} - 6 x + 5 = 0

f^{2} - 50 f = 0

What are the solutions to the equation 0=-16x^2+35x+6.5 ?
The solutions to the equation 0=-16x^2+35x+6.5 are x=-(-35+sqrt(1641))/(32),x=(35+sqrt(1641))/(32)
Find the zeros of 0=-16x^2+35x+6.5
The zeros of 0=-16x^2+35x+6.5 are x=-(-35+sqrt(1641))/(32),x=(35+sqrt(1641))/(32)