What are the solutions to the equation p^2-8p=-55 ?

The solutions to the equation p^2-8p=-55 are p=4+sqrt(39)i,p=4-sqrt(39)i

Find the zeros of p^2-8p=-55

The zeros of p^2-8p=-55 are p=4+sqrt(39)i,p=4-sqrt(39)i

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p^{2} - 8 p = - 55

p = 4 + 39 i, p = 4 - 39 i

Solution steps

p^{2} - 8 p = - 55

Move

55

to the left side

p^{2} - 8 p + 55 = 0

Solve with the quadratic formula

p_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot 55}{2 \cdot 1}

Simplify

(- 8)^{2} - 4 \cdot 1 \cdot 55 : 239 i

p_{1, 2} = \frac{- ( - 8 ) \pm 2 39 i}{2 \cdot 1}

Separate the solutions

p_{1} = \frac{- ( - 8 ) + 2 39 i}{2 \cdot 1}, p_{2} = \frac{- ( - 8 ) - 2 39 i}{2 \cdot 1}

p = \frac{- ( - 8 ) + 2 39 i}{2 \cdot 1} : 4 + 39 i

p = \frac{- ( - 8 ) - 2 39 i}{2 \cdot 1} : 4 - 39 i

The solutions to the quadratic equation are:

p = 4 + 39 i, p = 4 - 39 i

9 y^{2} = 1

2 y^{2} - 2 y = 0

3^{2} + 1 1^{2} = c^{2}

4 z^{2} + 4 z - 143 = 0

x^{2} + 16 x + 80 = 0

What are the solutions to the equation p^2-8p=-55 ?
The solutions to the equation p^2-8p=-55 are p=4+sqrt(39)i,p=4-sqrt(39)i
Find the zeros of p^2-8p=-55
The zeros of p^2-8p=-55 are p=4+sqrt(39)i,p=4-sqrt(39)i