What are the solutions to the equation n^2+11n-26=0 ?

The solutions to the equation n^2+11n-26=0 are n=2,n=-13

Find the zeros of n^2+11n-26=0

The zeros of n^2+11n-26=0 are n=2,n=-13

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n^{2} + 11 n - 26 = 0

n = 2, n = - 13

Solution steps

n^{2} + 11 n - 26 = 0

Solve with the quadratic formula

n_{1, 2} = \frac{- 11 \pm 1 1 ^{2} - 4 \cdot 1 \cdot ( - 26 )}{2 \cdot 1}

1 1^{2} - 4 \cdot 1 \cdot (- 26) = 15

n_{1, 2} = \frac{- 11 \pm 15}{2 \cdot 1}

Separate the solutions

n_{1} = \frac{- 11 + 15}{2 \cdot 1}, n_{2} = \frac{- 11 - 15}{2 \cdot 1}

n = \frac{- 11 + 15}{2 \cdot 1} : 2

n = \frac{- 11 - 15}{2 \cdot 1} : - 13

The solutions to the quadratic equation are:

n = 2, n = - 13

(x + 3) x = 10

3 x (x - 1) = 5 (x - 1)

a^{2} = 21

- x^{2} + 7 x + 12 = 0

2 (x + 3) - x^{2} - 3 x = 0

What are the solutions to the equation n^2+11n-26=0 ?
The solutions to the equation n^2+11n-26=0 are n=2,n=-13
Find the zeros of n^2+11n-26=0
The zeros of n^2+11n-26=0 are n=2,n=-13