What are the solutions to the equation 25a^2-60a+36=18 ?

The solutions to the equation 25a^2-60a+36=18 are a=(3(2+sqrt(2)))/5 ,a=(3(2-sqrt(2)))/5

Find the zeros of 25a^2-60a+36=18

The zeros of 25a^2-60a+36=18 are a=(3(2+sqrt(2)))/5 ,a=(3(2-sqrt(2)))/5

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25 a^{2} - 60 a + 36 = 18

a = \frac{3 ( 2 + 2 )}{5}, a = \frac{3 ( 2 - 2 )}{5}

Decimal Notation

a = 2.04852 \dots, a = 0.35147 \dots

Solution steps

25 a^{2} - 60 a + 36 = 18

Move

18

to the left side

25 a^{2} - 60 a + 18 = 0

Solve with the quadratic formula

a_{1, 2} = \frac{- ( - 60 ) \pm ( - 60 ) ^{2} - 4 \cdot 25 \cdot 18}{2 \cdot 25}

(- 60)^{2} - 4 \cdot 25 \cdot 18 = 302

a_{1, 2} = \frac{- ( - 60 ) \pm 30 2}{2 \cdot 25}

Separate the solutions

a_{1} = \frac{- ( - 60 ) + 30 2}{2 \cdot 25}, a_{2} = \frac{- ( - 60 ) - 30 2}{2 \cdot 25}

a = \frac{- ( - 60 ) + 30 2}{2 \cdot 25} : \frac{3 ( 2 + 2 )}{5}

a = \frac{- ( - 60 ) - 30 2}{2 \cdot 25} : \frac{3 ( 2 - 2 )}{5}

The solutions to the quadratic equation are:

a = \frac{3 ( 2 + 2 )}{5}, a = \frac{3 ( 2 - 2 )}{5}

x^{2} + 7 x - 20 = 0

(x + 8) (x + 8) = 0

3 u^{2} = 12 u - 6

6 (x - 1) - 6 (x - 2) = (x - 2) (x - 1)

- 15 x^{2} + 15 = 0

What are the solutions to the equation 25a^2-60a+36=18 ?
The solutions to the equation 25a^2-60a+36=18 are a=(3(2+sqrt(2)))/5 ,a=(3(2-sqrt(2)))/5
Find the zeros of 25a^2-60a+36=18
The zeros of 25a^2-60a+36=18 are a=(3(2+sqrt(2)))/5 ,a=(3(2-sqrt(2)))/5