What are the solutions to the equation x^2-15x+25=0 ?

The solutions to the equation x^2-15x+25=0 are x=(15+5sqrt(5))/2 ,x=(15-5sqrt(5))/2

Find the zeros of x^2-15x+25=0

The zeros of x^2-15x+25=0 are x=(15+5sqrt(5))/2 ,x=(15-5sqrt(5))/2

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x^{2} - 15 x + 25 = 0

x = \frac{15 + 5 5}{2}, x = \frac{15 - 5 5}{2}

Decimal Notation

x = 13.09016 \dots, x = 1.90983 \dots

Solution steps

x^{2} - 15 x + 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 15 ) \pm ( - 15 ) ^{2} - 4 \cdot 1 \cdot 25}{2 \cdot 1}

(- 15)^{2} - 4 \cdot 1 \cdot 25 = 55

x_{1, 2} = \frac{- ( - 15 ) \pm 5 5}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 15 ) + 5 5}{2 \cdot 1}, x_{2} = \frac{- ( - 15 ) - 5 5}{2 \cdot 1}

x = \frac{- ( - 15 ) + 5 5}{2 \cdot 1} : \frac{15 + 5 5}{2}

x = \frac{- ( - 15 ) - 5 5}{2 \cdot 1} : \frac{15 - 5 5}{2}

The solutions to the quadratic equation are:

x = \frac{15 + 5 5}{2}, x = \frac{15 - 5 5}{2}

\frac{1}{5} x^{2} + 2 x + 5 = 0

6 x^{2} + 10 x = 4 - 10 x - 6 x^{2}

x^{2} - 7 x = 12

x + 1 = (x - 1)^{2}

6 x^{2} + 7 x = 12

What are the solutions to the equation x^2-15x+25=0 ?
The solutions to the equation x^2-15x+25=0 are x=(15+5sqrt(5))/2 ,x=(15-5sqrt(5))/2
Find the zeros of x^2-15x+25=0
The zeros of x^2-15x+25=0 are x=(15+5sqrt(5))/2 ,x=(15-5sqrt(5))/2