What are the solutions to the equation y^2-5y+25/4 =0 ?

The solutions to the equation y^2-5y+25/4 =0 are y= 5/2

Find the zeros of y^2-5y+25/4 =0

The zeros of y^2-5y+25/4 =0 are y= 5/2

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y^{2} - 5 y + \frac{25}{4} = 0

y = \frac{5}{2}

Decimal Notation

y = 2.5

Solution steps

y^{2} - 5 y + \frac{25}{4} = 0

Multiply both sides by

4

4 y^{2} - 20 y + 25 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 4 \cdot 25}{2 \cdot 4}

(- 20)^{2} - 4 \cdot 4 \cdot 25 = 0

y_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 4}

y = \frac{- ( - 20 )}{2 \cdot 4}

\frac{- ( - 20 )}{2 \cdot 4} = \frac{5}{2}

y = \frac{5}{2}

The solution to the quadratic equation is:

y = \frac{5}{2}

x^{2} - 20 x - 50 = 0

x^{2} - 13 x - 18 = 0

3 x^{2} - 9 x - 20 = x^{2} + 5 x + 16

n^{2} - 4 n - 68 = - 8

6 x = x^{2} + 9

What are the solutions to the equation y^2-5y+25/4 =0 ?
The solutions to the equation y^2-5y+25/4 =0 are y= 5/2
Find the zeros of y^2-5y+25/4 =0
The zeros of y^2-5y+25/4 =0 are y= 5/2