What are the solutions to the equation 4x^2+34x-25=0 ?

The solutions to the equation 4x^2+34x-25=0 are x=(-17+sqrt(389))/4 ,x=-(17+sqrt(389))/4

Find the zeros of 4x^2+34x-25=0

The zeros of 4x^2+34x-25=0 are x=(-17+sqrt(389))/4 ,x=-(17+sqrt(389))/4

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4 x^{2} + 34 x - 25 = 0

x = \frac{- 17 + 389}{4}, x = - \frac{17 + 389}{4}

Decimal Notation

x = 0.68077 \dots, x = - 9.18077 \dots

Solution steps

4 x^{2} + 34 x - 25 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 34 \pm 3 4 ^{2} - 4 \cdot 4 ( - 25 )}{2 \cdot 4}

3 4^{2} - 4 \cdot 4 (- 25) = 2389

x_{1, 2} = \frac{- 34 \pm 2 389}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 34 + 2 389}{2 \cdot 4}, x_{2} = \frac{- 34 - 2 389}{2 \cdot 4}

x = \frac{- 34 + 2 389}{2 \cdot 4} : \frac{- 17 + 389}{4}

x = \frac{- 34 - 2 389}{2 \cdot 4} : - \frac{17 + 389}{4}

The solutions to the quadratic equation are:

x = \frac{- 17 + 389}{4}, x = - \frac{17 + 389}{4}

49 x^{2} - 7 x - \frac{3}{4}

5 x^{2} + 3 x + 7 = 0

(m + 4) x^{2} - 2 m x + 2 = 0

- t^{2} + 78 t + 460 = 1581

12 x^{2} + 24 = - 40

What are the solutions to the equation 4x^2+34x-25=0 ?
The solutions to the equation 4x^2+34x-25=0 are x=(-17+sqrt(389))/4 ,x=-(17+sqrt(389))/4
Find the zeros of 4x^2+34x-25=0
The zeros of 4x^2+34x-25=0 are x=(-17+sqrt(389))/4 ,x=-(17+sqrt(389))/4