What are the solutions to the equation 8x^2+2=-8x ?

The solutions to the equation 8x^2+2=-8x are x=-1/2

Find the zeros of 8x^2+2=-8x

The zeros of 8x^2+2=-8x are x=-1/2

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8 x^{2} + 2 = - 8 x

x = - \frac{1}{2}

Decimal Notation

x = - 0.5

Solution steps

8 x^{2} + 2 = - 8 x

Move

8 x

to the left side

8 x^{2} + 2 + 8 x = 0

Write in the standard form

a x^{2} + b x + c = 0

8 x^{2} + 8 x + 2 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 8 \cdot 2}{2 \cdot 8}

8^{2} - 4 \cdot 8 \cdot 2 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 8}

x = \frac{- 8}{2 \cdot 8}

\frac{- 8}{2 \cdot 8} = - \frac{1}{2}

x = - \frac{1}{2}

The solution to the quadratic equation is:

x = - \frac{1}{2}

2 x^{2} - \frac{1}{3} x

0 = 2 x^{2} + 4 x + 2

x, z = 4 + x^{2} + y^{2}

x^{2} + 4 x - 9 = - 6

5 z - 5 z^{2} = 1.2

What are the solutions to the equation 8x^2+2=-8x ?
The solutions to the equation 8x^2+2=-8x are x=-1/2
Find the zeros of 8x^2+2=-8x
The zeros of 8x^2+2=-8x are x=-1/2