What are the solutions to the equation 0=2x-x^2 ?

The solutions to the equation 0=2x-x^2 are x=0,x=2

Find the zeros of 0=2x-x^2

The zeros of 0=2x-x^2 are x=0,x=2

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0 = 2 x - x^{2}

x = 0, x = 2

Solution steps

0 = 2 x - x^{2}

Switch sides

2 x - x^{2} = 0

Write in the standard form

a x^{2} + b x + c = 0

- x^{2} + 2 x = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 ( - 1 ) \cdot 0}{2 ( - 1 )}

2^{2} - 4 (- 1) \cdot 0 = 2

x_{1, 2} = \frac{- 2 \pm 2}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- 2 + 2}{2 ( - 1 )}, x_{2} = \frac{- 2 - 2}{2 ( - 1 )}

x = \frac{- 2 + 2}{2 ( - 1 )} : 0

x = \frac{- 2 - 2}{2 ( - 1 )} : 2

The solutions to the quadratic equation are:

x = 0, x = 2

q, p = 2 + \frac{1}{5} q + \frac{1}{20} q^{2}

4 x^{2} - 3 x = 2

(10 - x) (- 12 - x) + 40 = 0

x (4 x - 1) = 3 x (x - 2) + 6

x, x^{2} - k x + 16 = 0

What are the solutions to the equation 0=2x-x^2 ?
The solutions to the equation 0=2x-x^2 are x=0,x=2
Find the zeros of 0=2x-x^2
The zeros of 0=2x-x^2 are x=0,x=2