What are the solutions to the equation -2x^2-6x-1=0 ?

The solutions to the equation -2x^2-6x-1=0 are x=-(3+sqrt(7))/2 ,x=-(3-sqrt(7))/2

Find the zeros of -2x^2-6x-1=0

The zeros of -2x^2-6x-1=0 are x=-(3+sqrt(7))/2 ,x=-(3-sqrt(7))/2

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- 2 x^{2} - 6 x - 1 = 0

x = - \frac{3 + 7}{2}, x = - \frac{3 - 7}{2}

Decimal Notation

x = - 2.82287 \dots, x = - 0.17712 \dots

Solution steps

- 2 x^{2} - 6 x - 1 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 2 ) ( - 1 )}{2 ( - 2 )}

(- 6)^{2} - 4 (- 2) (- 1) = 27

x_{1, 2} = \frac{- ( - 6 ) \pm 2 7}{2 ( - 2 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 7}{2 ( - 2 )}, x_{2} = \frac{- ( - 6 ) - 2 7}{2 ( - 2 )}

x = \frac{- ( - 6 ) + 2 7}{2 ( - 2 )} : - \frac{3 + 7}{2}

x = \frac{- ( - 6 ) - 2 7}{2 ( - 2 )} : - \frac{3 - 7}{2}

The solutions to the quadratic equation are:

x = - \frac{3 + 7}{2}, x = - \frac{3 - 7}{2}

- 5 = x (- 0.01 x - 0.4)

9 p^{2} - 12 p - 2 = 0

10 x^{2} - 2 (x - 1) + 10 = 9 (x^{2} + 1)

p^{2} - 50 = 0

p^{2} = 81

What are the solutions to the equation -2x^2-6x-1=0 ?
The solutions to the equation -2x^2-6x-1=0 are x=-(3+sqrt(7))/2 ,x=-(3-sqrt(7))/2
Find the zeros of -2x^2-6x-1=0
The zeros of -2x^2-6x-1=0 are x=-(3+sqrt(7))/2 ,x=-(3-sqrt(7))/2