What are the solutions to the equation 40^2+9^2=c^2 ?

The solutions to the equation 40^2+9^2=c^2 are c=41,c=-41

Find the zeros of 40^2+9^2=c^2

The zeros of 40^2+9^2=c^2 are c=41,c=-41

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

4 0^{2} + 9^{2} = c^{2}

c = 41, c = - 41

Solution steps

4 0^{2} + 9^{2} = c^{2}

Switch sides

c^{2} = 4 0^{2} + 9^{2}

Simplify

4 0^{2} + 9^{2} : 1681

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

c = 1681, c = - 1681

1681 = 41

- 1681 = - 41

c = 41, c = - 41

2 x^{2} + 4 x - 3

360 - 156 x + 12 x^{2} = 0

9 x^{2} = - 27

4 (x + 1)^{2} = 0

x^{2} - 17 = - 1 - 1

What are the solutions to the equation 40^2+9^2=c^2 ?
The solutions to the equation 40^2+9^2=c^2 are c=41,c=-41
Find the zeros of 40^2+9^2=c^2
The zeros of 40^2+9^2=c^2 are c=41,c=-41