What are the solutions to the equation x^2-5/6 x+2/3 =0 ?

The solutions to the equation x^2-5/6 x+2/3 =0 are x= 5/12+i(sqrt(71))/(12),x= 5/12-i(sqrt(71))/(12)

Find the zeros of x^2-5/6 x+2/3 =0

The zeros of x^2-5/6 x+2/3 =0 are x= 5/12+i(sqrt(71))/(12),x= 5/12-i(sqrt(71))/(12)

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x^{2} - \frac{5}{6} x + \frac{2}{3} = 0

x = \frac{5}{12} + i \frac{71}{12}, x = \frac{5}{12} - i \frac{71}{12}

Solution steps

x^{2} - \frac{5}{6} x + \frac{2}{3} = 0

Find Least Common Multiplier of

6, 3 : 6

Multiply by LCM=

6

x^{2} \cdot 6 - \frac{5}{6} x \cdot 6 + \frac{2}{3} \cdot 6 = 0 \cdot 6

Simplify

6 x^{2} - 5 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 5 ) \pm ( - 5 ) ^{2} - 4 \cdot 6 \cdot 4}{2 \cdot 6}

Simplify

(- 5)^{2} - 4 \cdot 6 \cdot 4 : 71 i

x_{1, 2} = \frac{- ( - 5 ) \pm 71 i}{2 \cdot 6}

Separate the solutions

x_{1} = \frac{- ( - 5 ) + 71 i}{2 \cdot 6}, x_{2} = \frac{- ( - 5 ) - 71 i}{2 \cdot 6}

x = \frac{- ( - 5 ) + 71 i}{2 \cdot 6} : \frac{5}{12} + i \frac{71}{12}

x = \frac{- ( - 5 ) - 71 i}{2 \cdot 6} : \frac{5}{12} - i \frac{71}{12}

The solutions to the quadratic equation are:

x = \frac{5}{12} + i \frac{71}{12}, x = \frac{5}{12} - i \frac{71}{12}

3 x^{2} + 7 = 7 x

2 p^{2} - 5 p - 3 = 0

y^{2} - 3 = y - y^{2}

x^{2} + 11 x - 6 = 0

10 x^{2} + 37 x - 12 = 0

What are the solutions to the equation x^2-5/6 x+2/3 =0 ?
The solutions to the equation x^2-5/6 x+2/3 =0 are x= 5/12+i(sqrt(71))/(12),x= 5/12-i(sqrt(71))/(12)
Find the zeros of x^2-5/6 x+2/3 =0
The zeros of x^2-5/6 x+2/3 =0 are x= 5/12+i(sqrt(71))/(12),x= 5/12-i(sqrt(71))/(12)