What are the solutions to the equation -(x-3)^2-7=0 ?

The solutions to the equation -(x-3)^2-7=0 are x=sqrt(7)i+3,x=-sqrt(7)i+3

Find the zeros of -(x-3)^2-7=0

The zeros of -(x-3)^2-7=0 are x=sqrt(7)i+3,x=-sqrt(7)i+3

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- (x - 3)^{2} - 7 = 0

x = 7 i + 3, x = - 7 i + 3

Solution steps

- (x - 3)^{2} - 7 = 0

Move

7

to the right side

- (x - 3)^{2} = 7

Divide both sides by

- 1

(x - 3)^{2} = - 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 3 = - 7 : x = 7 i + 3

Solve

x - 3 = - - 7 : x = - 7 i + 3

The solutions to the quadratic equation are:

x = 7 i + 3, x = - 7 i + 3

2 X^{2} - 7 X + 3 = 0

2 x (5 - 4 x) - 6 (3 x^{2} + 1) = 2 (2 x^{2} - 4)

3 x^{2} + 72 = 0

x^{2} - 27 x + 180 = 0

x^{2} + 11 x - 2 = 0

What are the solutions to the equation -(x-3)^2-7=0 ?
The solutions to the equation -(x-3)^2-7=0 are x=sqrt(7)i+3,x=-sqrt(7)i+3
Find the zeros of -(x-3)^2-7=0
The zeros of -(x-3)^2-7=0 are x=sqrt(7)i+3,x=-sqrt(7)i+3