What are the solutions to the equation 7x^2-4x=-3 ?

The solutions to the equation 7x^2-4x=-3 are x= 2/7+i(sqrt(17))/7 ,x= 2/7-i(sqrt(17))/7

Find the zeros of 7x^2-4x=-3

The zeros of 7x^2-4x=-3 are x= 2/7+i(sqrt(17))/7 ,x= 2/7-i(sqrt(17))/7

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7 x^{2} - 4 x = - 3

x = \frac{2}{7} + i \frac{17}{7}, x = \frac{2}{7} - i \frac{17}{7}

Solution steps

7 x^{2} - 4 x = - 3

Move

3

to the left side

7 x^{2} - 4 x + 3 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 4 ) \pm ( - 4 ) ^{2} - 4 \cdot 7 \cdot 3}{2 \cdot 7}

Simplify

(- 4)^{2} - 4 \cdot 7 \cdot 3 : 217 i

x_{1, 2} = \frac{- ( - 4 ) \pm 2 17 i}{2 \cdot 7}

Separate the solutions

x_{1} = \frac{- ( - 4 ) + 2 17 i}{2 \cdot 7}, x_{2} = \frac{- ( - 4 ) - 2 17 i}{2 \cdot 7}

x = \frac{- ( - 4 ) + 2 17 i}{2 \cdot 7} : \frac{2}{7} + i \frac{17}{7}

x = \frac{- ( - 4 ) - 2 17 i}{2 \cdot 7} : \frac{2}{7} - i \frac{17}{7}

The solutions to the quadratic equation are:

x = \frac{2}{7} + i \frac{17}{7}, x = \frac{2}{7} - i \frac{17}{7}

2 x^{2} + 38 x + 180 = 0

3 x^{2} - 15 x = 72

6 u^{2} + 4 u + 11 = 0

x, y (x - 3) x = x^{2} - 3 x + 2

(3 x)^{2} - x^{2} = 1800

What are the solutions to the equation 7x^2-4x=-3 ?
The solutions to the equation 7x^2-4x=-3 are x= 2/7+i(sqrt(17))/7 ,x= 2/7-i(sqrt(17))/7
Find the zeros of 7x^2-4x=-3
The zeros of 7x^2-4x=-3 are x= 2/7+i(sqrt(17))/7 ,x= 2/7-i(sqrt(17))/7