What are the solutions to the equation (d+3)^2=7 ?

The solutions to the equation (d+3)^2=7 are d=sqrt(7)-3,d=-sqrt(7)-3

Find the zeros of (d+3)^2=7

The zeros of (d+3)^2=7 are d=sqrt(7)-3,d=-sqrt(7)-3

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(d + 3)^{2} = 7

d = 7 - 3, d = - 7 - 3

Decimal Notation

d = - 0.35424 \dots, d = - 5.64575 \dots

Solution steps

(d + 3)^{2} = 7

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

d + 3 = 7 : d = 7 - 3

Solve

d + 3 = - 7 : d = - 7 - 3

The solutions to the quadratic equation are:

d = 7 - 3, d = - 7 - 3

x^{2} - 2 x - \frac{1}{2} = 0

y^{2} - 12 y

y^{2} - 16 y

r^{2} = 2

y^{2} - 24 y

What are the solutions to the equation (d+3)^2=7 ?
The solutions to the equation (d+3)^2=7 are d=sqrt(7)-3,d=-sqrt(7)-3
Find the zeros of (d+3)^2=7
The zeros of (d+3)^2=7 are d=sqrt(7)-3,d=-sqrt(7)-3