What are the solutions to the equation 5x^2+27x+10=0 ?

The solutions to the equation 5x^2+27x+10=0 are x=-2/5 ,x=-5

Find the zeros of 5x^2+27x+10=0

The zeros of 5x^2+27x+10=0 are x=-2/5 ,x=-5

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5 x^{2} + 27 x + 10 = 0

x = - \frac{2}{5}, x = - 5

Decimal Notation

x = - 0.4, x = - 5

Solution steps

5 x^{2} + 27 x + 10 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 27 \pm 2 7 ^{2} - 4 \cdot 5 \cdot 10}{2 \cdot 5}

2 7^{2} - 4 \cdot 5 \cdot 10 = 23

x_{1, 2} = \frac{- 27 \pm 23}{2 \cdot 5}

Separate the solutions

x_{1} = \frac{- 27 + 23}{2 \cdot 5}, x_{2} = \frac{- 27 - 23}{2 \cdot 5}

x = \frac{- 27 + 23}{2 \cdot 5} : - \frac{2}{5}

x = \frac{- 27 - 23}{2 \cdot 5} : - 5

The solutions to the quadratic equation are:

x = - \frac{2}{5}, x = - 5

x, 3 x^{2} + k x + 3 = 0

x^{2} + 13 x = - 30

b^{2} + 13 b + 40 = 0

12 = 8 x - x^{2}

x^{2} - 2 x + 3 = 0

What are the solutions to the equation 5x^2+27x+10=0 ?
The solutions to the equation 5x^2+27x+10=0 are x=-2/5 ,x=-5
Find the zeros of 5x^2+27x+10=0
The zeros of 5x^2+27x+10=0 are x=-2/5 ,x=-5