What are the solutions to the equation x^2+2x-9.6=0 ?

The solutions to the equation x^2+2x-9.6=0 are x=(-5+sqrt(265))/5 ,x=-(5+sqrt(265))/5

Find the zeros of x^2+2x-9.6=0

The zeros of x^2+2x-9.6=0 are x=(-5+sqrt(265))/5 ,x=-(5+sqrt(265))/5

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x^{2} + 2 x - 9.6 = 0

x = \frac{- 5 + 265}{5}, x = - \frac{5 + 265}{5}

Decimal Notation

x = 2.25576 \dots, x = - 4.25576 \dots

Solution steps

x^{2} + 2 x - 9.6 = 0

Multiply both sides by

10

10 x^{2} + 20 x - 96 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 20 \pm 2 0 ^{2} - 4 \cdot 10 ( - 96 )}{2 \cdot 10}

2 0^{2} - 4 \cdot 10 (- 96) = 4265

x_{1, 2} = \frac{- 20 \pm 4 265}{2 \cdot 10}

Separate the solutions

x_{1} = \frac{- 20 + 4 265}{2 \cdot 10}, x_{2} = \frac{- 20 - 4 265}{2 \cdot 10}

x = \frac{- 20 + 4 265}{2 \cdot 10} : \frac{- 5 + 265}{5}

x = \frac{- 20 - 4 265}{2 \cdot 10} : - \frac{5 + 265}{5}

The solutions to the quadratic equation are:

x = \frac{- 5 + 265}{5}, x = - \frac{5 + 265}{5}

(x - 2)^{2} + 3 x = 3 + (1 - 2 x)^{2}

4 x - 3 = 2 x^{2} + 5 x - 6

2 x^{2} + 25 x - 75 = 0

9 x^{2} + 6 x + 82 = 0

a^{2} + 9^{2} = 4 1^{2}

What are the solutions to the equation x^2+2x-9.6=0 ?
The solutions to the equation x^2+2x-9.6=0 are x=(-5+sqrt(265))/5 ,x=-(5+sqrt(265))/5
Find the zeros of x^2+2x-9.6=0
The zeros of x^2+2x-9.6=0 are x=(-5+sqrt(265))/5 ,x=-(5+sqrt(265))/5