What are the solutions to the equation x^2+25=16 ?

The solutions to the equation x^2+25=16 are x=3i,x=-3i

Find the zeros of x^2+25=16

The zeros of x^2+25=16 are x=3i,x=-3i

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x^{2} + 25 = 16

x = 3 i, x = - 3 i

Solution steps

x^{2} + 25 = 16

Move

25

to the right side

x^{2} = - 9

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 9, x = - - 9

- 9 = 3 i

- - 9 = - 3 i

x = 3 i, x = - 3 i

x, 2 x^{2} + 5 y^{2} + 12 x - 20 y + 38 = 0

3 x^{2} + 23 x + 14 = 0

\frac{5 x ^{2}}{6} - \frac{x ^{2}}{3} = 72

5 x^{2} - 21 x = 0

72 x^{2} + 12 x - 24 = 0

What are the solutions to the equation x^2+25=16 ?
The solutions to the equation x^2+25=16 are x=3i,x=-3i
Find the zeros of x^2+25=16
The zeros of x^2+25=16 are x=3i,x=-3i