What are the solutions to the equation x^2+8x+15=-4 ?

The solutions to the equation x^2+8x+15=-4 are x=-4+sqrt(3)i,x=-4-sqrt(3)i

Find the zeros of x^2+8x+15=-4

The zeros of x^2+8x+15=-4 are x=-4+sqrt(3)i,x=-4-sqrt(3)i

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x^{2} + 8 x + 15 = - 4

x = - 4 + 3 i, x = - 4 - 3 i

Solution steps

x^{2} + 8 x + 15 = - 4

Move

4

to the left side

x^{2} + 8 x + 19 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 1 \cdot 19}{2 \cdot 1}

Simplify

8^{2} - 4 \cdot 1 \cdot 19 : 23 i

x_{1, 2} = \frac{- 8 \pm 2 3 i}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 8 + 2 3 i}{2 \cdot 1}, x_{2} = \frac{- 8 - 2 3 i}{2 \cdot 1}

x = \frac{- 8 + 2 3 i}{2 \cdot 1} : - 4 + 3 i

x = \frac{- 8 - 2 3 i}{2 \cdot 1} : - 4 - 3 i

The solutions to the quadratic equation are:

x = - 4 + 3 i, x = - 4 - 3 i

12 x^{2} - 108 x + 216 = 0

3 x^{2} - x = 1

2 r^{2} + 9 r + 10 = 0

A, (A + B) (A + C) = A + BC

x^{2} + 18 x + 7 = 4

What are the solutions to the equation x^2+8x+15=-4 ?
The solutions to the equation x^2+8x+15=-4 are x=-4+sqrt(3)i,x=-4-sqrt(3)i
Find the zeros of x^2+8x+15=-4
The zeros of x^2+8x+15=-4 are x=-4+sqrt(3)i,x=-4-sqrt(3)i