What are the solutions to the equation 2x^2-9x-65=x^2-x ?

The solutions to the equation 2x^2-9x-65=x^2-x are x=13,x=-5

Find the zeros of 2x^2-9x-65=x^2-x

The zeros of 2x^2-9x-65=x^2-x are x=13,x=-5

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2 x^{2} - 9 x - 65 = x^{2} - x

x = 13, x = - 5

Solution steps

2 x^{2} - 9 x - 65 = x^{2} - x

Move

x

to the left side

2 x^{2} - 8 x - 65 = x^{2}

Move

x^{2}

to the left side

x^{2} - 8 x - 65 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 8 ) \pm ( - 8 ) ^{2} - 4 \cdot 1 \cdot ( - 65 )}{2 \cdot 1}

(- 8)^{2} - 4 \cdot 1 \cdot (- 65) = 18

x_{1, 2} = \frac{- ( - 8 ) \pm 18}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 8 ) + 18}{2 \cdot 1}, x_{2} = \frac{- ( - 8 ) - 18}{2 \cdot 1}

x = \frac{- ( - 8 ) + 18}{2 \cdot 1} : 13

x = \frac{- ( - 8 ) - 18}{2 \cdot 1} : - 5

The solutions to the quadratic equation are:

x = 13, x = - 5

2 x^{2} - 17 x = 9

s^{2} + 3 s + 4 = 0

x, 3 x^{2} + 4 m x + 3 = 0

(x + 2) (x + 3) = 5 x + 55

(3 x + 2)^{2} = 25

What are the solutions to the equation 2x^2-9x-65=x^2-x ?
The solutions to the equation 2x^2-9x-65=x^2-x are x=13,x=-5
Find the zeros of 2x^2-9x-65=x^2-x
The zeros of 2x^2-9x-65=x^2-x are x=13,x=-5