What are the solutions to the equation -x^2+7-6x=2 ?

The solutions to the equation -x^2+7-6x=2 are x=-3-sqrt(14),x=sqrt(14)-3

Find the zeros of -x^2+7-6x=2

The zeros of -x^2+7-6x=2 are x=-3-sqrt(14),x=sqrt(14)-3

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- x^{2} + 7 - 6 x = 2

x = - 3 - 14, x = 14 - 3

Decimal Notation

x = - 6.74165 \dots, x = 0.74165 \dots

Solution steps

- x^{2} + 7 - 6 x = 2

Move

2

to the left side

- x^{2} - 6 x + 5 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 6 ) \pm ( - 6 ) ^{2} - 4 ( - 1 ) \cdot 5}{2 ( - 1 )}

(- 6)^{2} - 4 (- 1) \cdot 5 = 214

x_{1, 2} = \frac{- ( - 6 ) \pm 2 14}{2 ( - 1 )}

Separate the solutions

x_{1} = \frac{- ( - 6 ) + 2 14}{2 ( - 1 )}, x_{2} = \frac{- ( - 6 ) - 2 14}{2 ( - 1 )}

x = \frac{- ( - 6 ) + 2 14}{2 ( - 1 )} : - 3 - 14

x = \frac{- ( - 6 ) - 2 14}{2 ( - 1 )} : 14 - 3

The solutions to the quadratic equation are:

x = - 3 - 14, x = 14 - 3

(y + 2)^{2} + 152 = 0

- x^{2} + 100 x - 2500 = 0

c^{2} - 9 = 0

\frac{x ^{2}}{2} + \frac{x}{2} = 10

- 3 x = 5 x^{2}

What are the solutions to the equation -x^2+7-6x=2 ?
The solutions to the equation -x^2+7-6x=2 are x=-3-sqrt(14),x=sqrt(14)-3
Find the zeros of -x^2+7-6x=2
The zeros of -x^2+7-6x=2 are x=-3-sqrt(14),x=sqrt(14)-3