What are the solutions to the equation (2x-5)(3x+8)=0 ?

The solutions to the equation (2x-5)(3x+8)=0 are x= 5/2 ,x=-8/3

Find the zeros of (2x-5)(3x+8)=0

The zeros of (2x-5)(3x+8)=0 are x= 5/2 ,x=-8/3

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(2 x - 5) (3 x + 8) = 0

x = \frac{5}{2}, x = - \frac{8}{3}

Decimal

x = 2.5, x = - 2.66666 \dots

Solution steps

(2 x - 5) (3 x + 8) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

2 x - 5 = 0 or 3 x + 8 = 0

Solve

2 x - 5 = 0 : x = \frac{5}{2}

Solve

3 x + 8 = 0 : x = - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{5}{2}, x = - \frac{8}{3}

(x - 3) (2 x + 5) = 0

- 3 k^{2} = - 48

a = x (25 - x)

5 x^{2} + 10 x + 1

27 x^{2} - 3 = 0

What are the solutions to the equation (2x-5)(3x+8)=0 ?
The solutions to the equation (2x-5)(3x+8)=0 are x= 5/2 ,x=-8/3
Find the zeros of (2x-5)(3x+8)=0
The zeros of (2x-5)(3x+8)=0 are x= 5/2 ,x=-8/3