What are the solutions to the equation 5x^2-4x+4/5 =0 ?

The solutions to the equation 5x^2-4x+4/5 =0 are x= 2/5

Find the zeros of 5x^2-4x+4/5 =0

The zeros of 5x^2-4x+4/5 =0 are x= 2/5

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5 x^{2} - 4 x + \frac{4}{5} = 0

x = \frac{2}{5}

Decimal Notation

x = 0.4

Solution steps

5 x^{2} - 4 x + \frac{4}{5} = 0

Multiply both sides by

5

25 x^{2} - 20 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 25 \cdot 4}{2 \cdot 25}

(- 20)^{2} - 4 \cdot 25 \cdot 4 = 0

x_{1, 2} = \frac{- ( - 20 ) \pm 0}{2 \cdot 25}

x = \frac{- ( - 20 )}{2 \cdot 25}

\frac{- ( - 20 )}{2 \cdot 25} = \frac{2}{5}

x = \frac{2}{5}

The solution to the quadratic equation is:

x = \frac{2}{5}

a, (a - b)^{2} = 0

x^{2} + 5 = 7 x - 1

- 9 x^{2} + 8 x + 7 = 0

m^{2} + 5 m

6 x^{2} + 25 x + 4 = 0

What are the solutions to the equation 5x^2-4x+4/5 =0 ?
The solutions to the equation 5x^2-4x+4/5 =0 are x= 2/5
Find the zeros of 5x^2-4x+4/5 =0
The zeros of 5x^2-4x+4/5 =0 are x= 2/5