What are the solutions to the equation 2a^2-5=0 ?

The solutions to the equation 2a^2-5=0 are a=sqrt(5/2),a=-sqrt(5/2)

Find the zeros of 2a^2-5=0

The zeros of 2a^2-5=0 are a=sqrt(5/2),a=-sqrt(5/2)

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2 a^{2} - 5 = 0

a = \frac{5}{2}, a = - \frac{5}{2}

Decimal Notation

a = 1.58113 \dots, a = - 1.58113 \dots

Solution steps

2 a^{2} - 5 = 0

Move

5

to the right side

2 a^{2} = 5

Divide both sides by

2

a^{2} = \frac{5}{2}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

a = \frac{5}{2}, a = - \frac{5}{2}

- 2 x^{2} + 6 x + 56 = 0

10 x^{2} + 2 x - 3 = 0

(2 x - 3)^{2} - (x - 5)^{2} = - 23

30 x^{2} - 60 = 0

x^{2} + 11 x = 60

What are the solutions to the equation 2a^2-5=0 ?
The solutions to the equation 2a^2-5=0 are a=sqrt(5/2),a=-sqrt(5/2)
Find the zeros of 2a^2-5=0
The zeros of 2a^2-5=0 are a=sqrt(5/2),a=-sqrt(5/2)