What are the solutions to the equation 16^2+25y^2-400=0 ?

The solutions to the equation 16^2+25y^2-400=0 are y= 12/5 ,y=-12/5

Find the zeros of 16^2+25y^2-400=0

The zeros of 16^2+25y^2-400=0 are y= 12/5 ,y=-12/5

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

1 6^{2} + 25 y^{2} - 400 = 0

y = \frac{12}{5}, y = - \frac{12}{5}

Decimal Notation

y = 2.4, y = - 2.4

Solution steps

1 6^{2} + 25 y^{2} - 400 = 0

Move

1 6^{2}

to the right side

25 y^{2} - 400 = - 256

Move

400

to the right side

25 y^{2} = 144

Divide both sides by

25

y^{2} = \frac{144}{25}

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

y = \frac{144}{25}, y = - \frac{144}{25}

\frac{144}{25} = \frac{12}{5}

- \frac{144}{25} = - \frac{12}{5}

y = \frac{12}{5}, y = - \frac{12}{5}

x, x^{2} y^{3} - 2 x y = 6 x + y + 1

y, x^{4} + 2 y^{2} = 6 x^{2} + 4 y - 5

2 x^{2} + 5 x + c = 0

5 x^{2} + 3 x

8 x^{2} = 81

What are the solutions to the equation 16^2+25y^2-400=0 ?
The solutions to the equation 16^2+25y^2-400=0 are y= 12/5 ,y=-12/5
Find the zeros of 16^2+25y^2-400=0
The zeros of 16^2+25y^2-400=0 are y= 12/5 ,y=-12/5